In a population of plants, the allele for long stems (s) is completely dominant over the allele for short stems (s). if 35% of the population has short stems, calculate the percentage of the population that is expected to be heterozygous (ss).

We solve the problem using the Hardy-Wineberg equation.

Let us start with the homozygous recessive percentage first,

q² = 35/100 = 0.35

We have the frequency for short stem (s) as q = √0.35 = 0.59

Solving for the frequency of long stem (S) by using the fact that,

p + q = 1

∴ p = 1 - q = 1 - 0.59 = 0.41

So the long stem (S) has a frequency of 0.41.

Now we can calculate 2pq which is the heterozygous alleles (Ss) frequency.

∴ 2pq = 2 x 0.59 x 0.41 = 0.48

Hence 48% of the population is heterozygous for long stem.

a "theory" a suggestion that is not 100 % accurate, or a figure. some people say its a theory because they of all the passed theory's about one subject. it depends sometimes theory might be accurate and sometimes they are.

the answer is d. exposing corruption in the church