Abox slides down an inclined plane with a uniform acceleration and attains a velocity of 27 m/s in 3 seconds from rest. find the final velocity and distance moves in 6 seconds (initially at rest)

In the given case, the final velocity after 6s is 54 m/s, and the distance covered by the object in 6s = 162m

To find out the final velocity and distance in 6 seconds first we need to find out the acceleration of the object

Given

initial velocity, u = 0 m/s

final velocity, v = 27 m/s

Time, t = 3 sec

Solution

Using the equation of motion

Putting the values:-

So the acceleration of the object is

Now for

t = 6 sec

Using the equation of motion

And using the value of acceleration a =

Now to calculate the distance covered in 6 sec, using the equation of motion

Putting the values

So, the final velocity after 6s is 54 m/s, and the distance covered by the object in 6s = 162m

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