Advanced Placement (AP), 30.07.2019 10:30 jstephanie644

Pls check if my answer is correct! 40 points! question: a circuit (picture attached) is shown. if light bulb a is removed, what would happen to the brightness of the other light bulbs (b, c, d)? assume the resistance of each resistor to be r, and the total voltage to be v. my the total resistance before a was removed: $r_t = (\frac{1}{ (\frac{1}{r})+ (\frac{1}{r}) + (\frac{1}{r }) })+r = \frac{4}{3}r$ the total resistance after a was removed: $r_t = (\frac{1}{ (\frac{1}{r})+ (\frac{1}{r}) + (\frac{1}{r }) }) = \frac{1}{3}r$ total current before a was removed: $i = \frac{v}{r} = \frac{v}{ \frac{4}{3} r} = \frac{3v}{4r}$ total current after a was removed: $i = \frac{v}{r} = \frac{v}{ \frac{1}{3} r} = \frac{3v}{r}$ current of light bulb b before a was removed (and c & d because they have same r and v as b): $v = v - ( \frac{3v}{4r}r) = v - ( \frac{3v}{4} ) = \frac{1}{4} v$ $i_b = \frac{v}{r} = \frac{v}{4r}$ current of light bulb b after a was removed (and c & d because they have same r and v as b): $v = ir = v - (\frac{3v}r} r) = v - 3v = -2v$ $i_b = \frac{v}{r} = \frac{-2v}{r}$ so, since $\frac{-2v}{r} \ \textless \ \frac{v}{4r}$ , the brightness of b, c, and d decreases because the current of all of them decrease.

Pls check if my answer is correct! 40 points! question: a circuit (picture attached) is shown. if

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