![\int\limits^{3}_{-3} {x^2f(x^3)} \, dx= \int\limits^{27}_{-27} \frac{f(u)}3 \, du \\=\frac{1}3\left[\int\limits^{0}_{-27} {f(u)} \, du+\int\limits^{27}_{0} {f(u)} \, du \right] (2)\\Observe:\int\limits^{0}_{-27} {f(u)} \, du=\int\limits^{27}_{0} {f(u)} du\; \text{ because f(x) is an even function}\\\text{Substitute the left hand side integral for the RHS in equation (2):}\\=\frac{1}3\left[2\int\limits^{27}_0 {f(u)} du\right]\\=\frac{1}3 (2)(12)=8](/tpl/images/1213/5975/e372e.png)
I am so confused please help asap! (calc, integrals) please explain as well
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Advanced Placement (AP), 23.03.2021 09:50 sabrinarasull1pe6s61
I am so confused please help asap! (calc, integrals) please explain as well
Answers: 3
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