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Calculus Help Please!! If integral^k_0 x/(x^2 + 4) dx = 1/2 ln(4), where k > 0, then k=
I know the answer is the square root of 12 but I don’t know how to get there.


Calculus Help Please!!

If integral^k_0 x/(x^2 + 4) dx = 1/2 ln(4), where k > 0, then k=
I know

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Answers: 2

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Calculus Help Please!! If integral^k_0 x/(x^2 + 4) dx = 1/2 ln(4), where k > 0, then k=
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