Advanced Placement (AP), 18.12.2020 02:20 natalie2sheffield

Can someone please help I think I know the answer just want to double check it

Answers: 1

Show answers

Answers

Answer from: loanyst99111

read below/use comments

Explanation:

I can't see them all clearly (such as D) so here is what I know;

A: well this one could be a possible answer BUT you could figure out most through the sides, although this is a VERY strong possible solution

B. -_- no

C. triangle... no

D. I can't see that very clearly but if so, I think this might be the answer? They look like 2 little triangles in which you will need to know sizes but I can't see what it is.

E. ._. just get the measurements.

Answer from: Quest

Answer: the interval on which the curve is concave up is (-∞, -1/2)====== $\displaystyle y = \int_{0}^x \frac{1}{1 + t + t^2} \; dt$ we find the interval where this curve is concave up by finding the interval in which the 2nd derivative is positive.differentiate the curve equation with respect to x $\begin{aligned} \frac{dy}{dx} & = \frac{d}{dx} \int_{0}^x \frac{1}{1 + t + t^2} \; dt \end{aligned}$ let the function f denote be the anti-derivative of the inside expression, i.e. a function such that $(d/dx)f(x) = 1/(1 + t + t^2)$ .then use the fundamental theorem of calculus: $\begin{aligned} \frac{dy}{dx} & = \frac{d}{dx} \int_{0}^x \frac{1}{1 + t + t^2} \; dt \\& = \frac{d}{dx} \big[ f(x) - f(0) \big] & & \text{\footnotesize apply ftc} \\ & = \frac{d}{dx}f(x) - 0 \\ & = \frac{1}{x + x + x^2} & & \text{\footnotesize since $\frac{d}{dx}f(x) = \frac{1}{1 + x + x^2}$ } \end{aligned}$ differentiate again to get second derivative. we can use chain rule with 1/x as the outside function and 1 + x + x² as the inside function $\begin{aligned} \frac{d}{dx} \left( \frac{dy}{dx} \right) & = \frac{d}{dx}\left(\frac{1}{1 + x + x^2} \right) \\ \frac{d^2y}{dx^2} & = \frac{-1}{\left(1 + x + x^2\right)^2} \cdot \tfrac{d}{dx}(1 + x + x^2) \\ & = \frac{-1}{\left(1 + x + x^2\right)^2} \cdot (1 + 2x) \\ & = \frac{-(1 + 2x)}{\left(1 + x + x^2\right)^2} \end{aligned}$ find critical numbers of the second derivative. these numbers are where the 2nd deriv. is undefined or zero.where the 2nd derivative is zero: set (d²y/dx²) to equal 0 and solve for x $\begin{aligned} 0 & = \frac{-(1 + 2x)}{\left(1 + x + x^2\right)^2} \\ 0 & = -(1+2x) \\ -1 & = 2x \\ x & = -1/2 \end{aligned}$ where the 2nd derivative is undefined: if the denominator is equal to zero, the derivative will be undefeined. attempting to solve the equation 1 + x + x² = 0results in a discriminant of $b^2 - 4ac = 1^2 - 4(1)(1) = -3$ meaning that the equal 1 + x + x² = 0 has no real solutions and therefore will never equal zero.======our only critical number is x = -1/2.this forms two intervals to test the sign for: (-∞, -1/2) and (-1/2, ∞)test values into the 2nd derivative for (-∞, -1/2)if we try x = -1, we get $\begin{aligned} \left.\frac{d^2y}{dx^2}\right|_{x = -1} & = \frac{-(1+2(-1))}{\left(1+(-1)+(-1)^2\right)^2} \\ & = \frac{-(1-2)}{1} \\ & = 1 \end{aligned}$ so the since the 2nd derivative of the curve is positive on the interval (-∞, -1/2), the curve is concave up on (-∞, -1/2)test values into the 2nd derivative for (-1/2, ∞)if we try x = 0, we get $\begin{aligned} \left.\frac{d^2y}{dx^2}\right|_{x = 0} & = \frac{-(1+2(0))}{\left(1+(0)+(0)^2\right)^2} \\ & = \frac{-(1)}{1} \\ & = -1 \end{aligned}$ so the since the 2nd derivative of the curve is positive on the interval (-∞, -1/2), the curve is concave down on (-∞, -1/2).the interval on which the curve is concave up is (-∞, -1/2)

Answer from: Quest

Is this english or something else

Other questions on the subject: Advanced Placement (AP)

Advanced Placement (AP), 22.06.2019 02:00, katelyn03anderson

Are children who act in rated ‘r’ movies allowed to see them? are eyebrows considered facial hair? at a movie theater which arm rest is yours? can a short person “talk down” to a taller person? can animals commit suicide? can you daydream at night? do bald people get dandruff? do coffins have lifetime guarantees? do dentists go to other dentists or do they just do it themselves? do prison buses have emergency exits? do sheep get static cling when they rub against one another? do stairs go up or down? do stuttering people stutter when they’re thinking to themselves? do they bury people with their braces on? do they have the word “dictionary” in the dictionary? do you yawn in your sleep? do your eyes change color when you die? how can something be “new” and “improved”? if it’s new, what was it improving on? how come only your fingers and toes get wrinkly in the shower and nothing else does? how come you never see a billboard being put up by the highway? how do you handcuff a one-armed man? how far east can you

Answers: 1

continue

Advanced Placement (AP), 23.06.2019 12:50, adeleinflores9402

Want free brainliest + free points? answer this correctly and i got you the majority of collisions are preventable through a. good defensive driving habits b. bad defensive driving habits c. good luck d. new technologies

Answers: 2

continue

Advanced Placement (AP), 23.06.2019 16:30, wirchakethan23

Problem 1: given: 14 coulombs of charge flow in an electrical circuit. the charge is pushed by a voltage difference if 8 volts. a) calculate the amount of work done in volt. coulombs. b.) calculate the work done in joules.

Answers: 1

continue

Advanced Placement (AP), 24.06.2019 03:30, amedaldafari

Hurry: the angle measures associated with which set of ordered pairs share the same reference angle? (-square-root 3/2, 1/2) , (-1/2, -square-root 3/2) (1/2, -square-root 3/2) , (-square-root 3/2, 1/2) (-1/2, -square-root 3/2), (1/2, square-root 3/2) (square-root 3/2, 1/2) , (1/2, square-root 3/2)

Answers: 1

continue

You know the right answer?

Can someone please help I think I know the answer just want to double check it
...