Can there be an inflection point when the third derivative equals 0? My critical point from the second derivative is x = 0. To check whether there is an inflection point, I plugged it into the 3rd derivative. If it is below or above 0, there is an inflection point. Mine is EQUAL to 0. Does this mean there is a possibility my inflection point is at (0, 0) or is it undefined? How do I check?

if triangle abc is congruent to triangle def, their interior angles are congruent, because congruent parts of congruent triangles are congruent (cpctc).

that means ∠d is congruent to ∠a; ∠d is equal to 8x - 2.

interior angles of all triangles add to equal 180 degrees, so you can set the sum of these interior angle values equal to 180 and solve for x.

180 = (8x - 2) + 22 + 72

180 = 8x - 2 + 22 + 72

180 = 8x + 92

88 = 8x

11 = x

x = 11

actually, no it isn't. when i was in junior high school, it was a blast. considering that it was a pre international baccalaureate school.

explanation: