2. (03.05 HC) The table below represents the velocity of a car as a function of time: Time (hour) x Velocity (miles/hours) y 0 50 1 52 2 54 3 56 Part A: What is the y-intercept of the function, and what does this tell you about the car? (4 points) Part B: Calculate the average rate of change of the function represented by the table between x = 1 to x = 3 hours, and tell what the average rate represents. (4 points) Part C: What would be the domain of the function if the velocity of the car was measured until it reached 60 miles/hour and the car does not change motion? (2 points) (10 points)

(A): When it asks for a y-intercept, it is basically asking what is the value of y when x=0. In this case, when x=0, y=50. So the y-intercept is 50.

(B): The avg. rate of change is the same as asking for slope. So we want to use slope formula -> m= \frac{y2-y1}{x2-x1}. Using the values in your table -> m =  \frac{56-52}{3-1} =  \frac{4}{2} =2

(C) You can generate a linear function with a y-intercept and a slope using the following formula -> y= (average rate of change)*x + y-intercept ->y= 2x+50 Then set y=60 and solve for x. Your domain is [0, solved value] with square brackets since you are including the endpoints.

Hope that helped!

Explanation:

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