Advanced Placement (AP), 24.09.2020 05:01 LiliGrey7612

A package delivery company currently has a fleet of trucks, three employees, and one warehouse. As more employees are hired, the warehouse becomes more crowded, and employees become less efficient. The company receives $5 per delivery and its costs are $120 per employee per day. If the company is a rational actor, what should it do to maximize its profit?

Answers: 3

Show answers

Answers

Answer from: Quest

i don't suggest being gay, while it's 2018 and everyone is coming out, it's not the best thing to do, not eveyone is okay with it for coming to my ted talk

Answer from: Quest

Answer: the interval on which the curve is concave up is (-∞, -1/2)====== $\displaystyle y = \int_{0}^x \frac{1}{1 + t + t^2} \; dt$ we find the interval where this curve is concave up by finding the interval in which the 2nd derivative is positive.differentiate the curve equation with respect to x $\begin{aligned} \frac{dy}{dx} & = \frac{d}{dx} \int_{0}^x \frac{1}{1 + t + t^2} \; dt \end{aligned}$ let the function f denote be the anti-derivative of the inside expression, i.e. a function such that $(d/dx)f(x) = 1/(1 + t + t^2)$ .then use the fundamental theorem of calculus: $\begin{aligned} \frac{dy}{dx} & = \frac{d}{dx} \int_{0}^x \frac{1}{1 + t + t^2} \; dt \\& = \frac{d}{dx} \big[ f(x) - f(0) \big] & & \text{\footnotesize apply ftc} \\ & = \frac{d}{dx}f(x) - 0 \\ & = \frac{1}{x + x + x^2} & & \text{\footnotesize since $\frac{d}{dx}f(x) = \frac{1}{1 + x + x^2}$ } \end{aligned}$ differentiate again to get second derivative. we can use chain rule with 1/x as the outside function and 1 + x + x² as the inside function $\begin{aligned} \frac{d}{dx} \left( \frac{dy}{dx} \right) & = \frac{d}{dx}\left(\frac{1}{1 + x + x^2} \right) \\ \frac{d^2y}{dx^2} & = \frac{-1}{\left(1 + x + x^2\right)^2} \cdot \tfrac{d}{dx}(1 + x + x^2) \\ & = \frac{-1}{\left(1 + x + x^2\right)^2} \cdot (1 + 2x) \\ & = \frac{-(1 + 2x)}{\left(1 + x + x^2\right)^2} \end{aligned}$ find critical numbers of the second derivative. these numbers are where the 2nd deriv. is undefined or zero.where the 2nd derivative is zero: set (d²y/dx²) to equal 0 and solve for x $\begin{aligned} 0 & = \frac{-(1 + 2x)}{\left(1 + x + x^2\right)^2} \\ 0 & = -(1+2x) \\ -1 & = 2x \\ x & = -1/2 \end{aligned}$ where the 2nd derivative is undefined: if the denominator is equal to zero, the derivative will be undefeined. attempting to solve the equation 1 + x + x² = 0results in a discriminant of $b^2 - 4ac = 1^2 - 4(1)(1) = -3$ meaning that the equal 1 + x + x² = 0 has no real solutions and therefore will never equal zero.======our only critical number is x = -1/2.this forms two intervals to test the sign for: (-∞, -1/2) and (-1/2, ∞)test values into the 2nd derivative for (-∞, -1/2)if we try x = -1, we get $\begin{aligned} \left.\frac{d^2y}{dx^2}\right|_{x = -1} & = \frac{-(1+2(-1))}{\left(1+(-1)+(-1)^2\right)^2} \\ & = \frac{-(1-2)}{1} \\ & = 1 \end{aligned}$ so the since the 2nd derivative of the curve is positive on the interval (-∞, -1/2), the curve is concave up on (-∞, -1/2)test values into the 2nd derivative for (-1/2, ∞)if we try x = 0, we get $\begin{aligned} \left.\frac{d^2y}{dx^2}\right|_{x = 0} & = \frac{-(1+2(0))}{\left(1+(0)+(0)^2\right)^2} \\ & = \frac{-(1)}{1} \\ & = -1 \end{aligned}$ so the since the 2nd derivative of the curve is positive on the interval (-∞, -1/2), the curve is concave down on (-∞, -1/2).the interval on which the curve is concave up is (-∞, -1/2)

Answer from: Quest

i don't know the answer

Answer from: Quest

answer: depends on time zone.

eastern: 10: 49

central: 9: 49

moutain: 8: 49

explanation:

Other questions on the subject: Advanced Placement (AP)

Advanced Placement (AP), 22.06.2019 15:00, eddsworldfrantic

What do the potential problems that each side anticipates reveal about the nature of the relationship between masters and indentured servants

Answers: 2

continue

Advanced Placement (AP), 23.06.2019 20:00, almighty3120

Ill mark brainliest to whoever answers first correctly hurry! a vehicle's is the entire piece of plastic that spans the front end of the passenger cabin. a. instrument panel b. control panel c. dashboard d. frontboard

Answers: 1

continue

Advanced Placement (AP), 24.06.2019 07:40, trevorhenyan51

Type the correct answer in each box. use = 3.14 and if necessary, round your answers to the nearest hundredth. the area of the largest cross section of a sphere and the circumference of the sphere are in the ratio 4: 1. cm. the area of the largest cross section is about the radius of the sphere is cm. the circumference of the sphere is about cm2. the volume of the sphere is about cm?

Answers: 1

continue

Advanced Placement (AP), 24.06.2019 08:00, 22norvd

What statement is true about all chemical changes? a) chemical changes can be undone. b) chemical changes cannot be reversed. c) chemical changes change the color of objects. eliminate d) chemical changes do not form new products.

Answers: 2

continue

You know the right answer?

A package delivery company currently has a fleet of trucks, three employees, and one warehouse. As m...