A light bulb with resistance of 80 12 is connected to a 9 V
battery. The electric current going through it is 0.1125 A. How
many electrons leave the battery every hour?

A. 6.98341 x 10^-19 electrons/ 1 hour

B. 0.17532 x 10^-29 electrons/ 1 hour

C. 2.53125 x 10^21 electrons/ 1 hour

D. 3.00029 x 10^17 electrons/ 1 hour

Your answer is 1190.25

Answer texture;

Answerpeople,vehicles,roadways.;

The answer is    (d) 7/2======we have    we also  have an integral      notice how function f splits up at x = 0. there's a left piece and a right pieceso we'll need to do the same thing with our integral: split it at x = 0we use a property of integrals that allows us to split up and sum:     notice that for the piecewise function f, the function has the equationf(x) = x when x  ≤ 0. so for the integral  , f(x) = x so it changes into      for the piecewise function f, the function has the equationf(x) = x+1  when x  > 0. for the integral  , we have    therefore, back to our splitted integral: