A ball is thrown into the air at a velocity of 44 feet per second. Its height in feet, h after t seconds is represented by the equation h=12t^2+44t+16 after how many seconds will the ball hit the ground

0.447 sec

Explanation:

velocity = distance/ time

distance 'h' is a function of time 't' given by

⇒ differentiating equation

⇒ velocity =

⇒ acceleration = = 24

deceleration due to gravity = -9.8 m/ =  - 9.8 x 3.281 = - 32.154 ft/

Net deceleration = 24 - 32.154 = - 8.15 ft/

at maximum height v = 0

= + 2ah

⇒  0 = + 2 (-8.15)h

⇒ h = 118.72 ft⇒

118.72 = 12 + 44t + 16

⇒ - 102.72 = 0

⇒  t = -44 ±     / (2 x 12)

t = 0.447 sec

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