Mathematics, 24.01.2021 16:30 wmaingrette1

Can someone please help

Answers: 3

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Answer from: lewisj53

$\boxed{ \boxed{ \tt{3. \: \: \: \: \underline{ \: 11.85}}}}$

$\boxed{ \boxed{ \tt{ \: 4. \: \: \: \: \: \: \: \underline{13 \sqrt{3} \: cm}}}}$

Step-by-step explanation:

First , A simple way how to remind the three basic trigonometric functions is by reminding the famous word " SOHCAHTOA". We divide the word in three words with three letters.

$\underline{ \underline{ \sf{SOH , \: CAH , \: TOA}}}$ :

The first letter of each word represents the name of the function.The second letter represents what's up the ratios sign.The third one represents what's at the bottom of the ratio sign.

We write :

$\sf{sin \: \theta = \frac{opposite}{hypotenuse} }$ $\sf{cos \: \theta = \frac{adjacent}{hypotenuse}}$ $\sf{tan \: \theta = \frac{opposite}{adjacent}}$

Now , Let's work on it :

3. Based on the figure ( 3 ) , we know the hypotenuse ( i.e 15 ) & the angle 53° & we have to find the opposite ( x ).

$\sf{ \sin(53) = \frac{opposite}{hypotenuse} }$

⇾ $\sf{0.79 = \frac{x}{15}}$

⇾ $\sf{x = 11.85}$

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5. Based on the figure ( 4 ) , we know the adjacent ( i.e 13 cm & the angle 60° & we have to find the opposite ( x ).

$\sf{ \tan(60}) = \frac{opposite}{adjacent}$

⇾ $\sf{ \sqrt{3} = \frac{x}{13} }$

⇾ $\sf{x = 13 \sqrt{3}}$ cm

And we're done !

Hope I helped ! ツ

Have a wonderful day / night ! ♡

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Answer from: Quest

8y^50

step-by-step explanation:

Answer from: Quest

see below

step-by-step explanation:

7. there are 10 data points in the set. the middle point is between 5 and 6. the middle point in the top half is 8 and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term point 8 = 100 point 3 = 88

iqr = 100-88 = 12

final point 8 = 93 point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6. b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical . there is an outlier for the males that skews the data

5. the iqr is a better measure of spread for the movies and basketball games. since the basketball game has an outlier, we do not want to use standard deviation for measurement.

3. the exam median is much higher than the class median. the median line is farther to the right on the exams

2. there is no way to tell what the means are from the box and whisker plots.