Duncan takes a break from studying and goes to the gym to swim laps. If swimming burns 6.55×105 calcal per hour, how many kilojoules does swimming burn in that same amount of time? In other words, convert 6.55×105 calcal to kilojoules

2.751x10^3KJ

Explanation:

The following were obtained from the question given:

Duncan burns 6.55×10^5 calcal per hour.

1 calorie = 4.2J

6.55×10^5 calories = 6.55×10^5 x 4.2 = 2.751x10^6J

Now we divide by 1000 to expressed in KJ i.e

2.751x10^6/1000 = 2.751x10^3KJ

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

the atomic mass is the bottom number on the element.

-steel jelly